Find the surface area of a cylinder with the following dimension: Height =10 ft. Radius =2 ft.
82πft2
78πft2
48πft2
81πft2
A
78πft2
B
81πft2
C
82πft2
D
48πft2
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Solution
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Surface area of cylinder is A=2πr(r+h)
Here, radius is r=2 ft and the height is h=10 ft.
Thus,
A=2π×2(2+10)=2π×2×12=48π
Hence, the surface area of the cylinder is 48π ft2.
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