Find the value of 199times 201-399894000139999400011

Question

Toppr Admin · Accepted Answer

Given-xA0-199-xD7-201-200-x2212-1-200-1-We know- a2-x2212-b2-a-x2212-b-a-b-Then-199-xD7-201-200-x2212-1-200-1-2002-x2212-12-40000-x2212-1-39999-Therefore- option C is correct-

Find the value of $199 \times 201$ .
$39989$
$40001$
$39999$
$400011$

Given, $199 \times 201$
$= (200 - 1) (200 + 1)$ .

We know, $a^{2} - b^{2} = (a - b) (a + b)$ .

Then,
$199 \times 201$
$= (200 - 1) (200 + 1)$
$= 200^{2} - 1^{2}$
$= 40000 - 1$
$= 39999$ .

Therefore, option $C$ is correct.

Find the value of 199×201.399894000139999400011

Given, 199×201=(200−1)(200+1).We know, a2−b2=(a−b)(a+b).Then,199×201=(200−1)(200+1)=2002−12=40000−1=39999.Therefore, option C is correct.

Find the value of $199 \times 201$ .
$39989$
$40001$
$39999$
$400011$

Given, $199 \times 201$
$= (200 - 1) (200 + 1)$ .

We know, $a^{2} - b^{2} = (a - b) (a + b)$ .

Then,
$199 \times 201$
$= (200 - 1) (200 + 1)$
$= 200^{2} - 1^{2}$
$= 40000 - 1$
$= 39999$ .

Therefore, option $C$ is correct.