Find the value of $703 - 1 + 1 - 400$ .

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703 - 1 + 1 - 400

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[\frac{1}{8}] + [\frac{1}{8} + \frac{1}{400}] + [\frac{1}{8} + \frac{1}{200}] + [\frac{1}{8} + \frac{3}{400}] + \dots + [\frac{1}{8} + \frac{399}{400}]

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Hydration energy ${Δ H}_{h y d r a} . (k J m o l^{- 1})$	Lattice energy $Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499	LiCl-840
$N a^{+}$ -390	NaCl-776
$K^{+}$ -305	KCl-703
$C l^{-}$ -382

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Hydration energy ${Δ H}_{h y d r a} . (k J m o l^{- 1})$	Lattice energy $Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499	LiCl-840
$N a^{+}$ -390	NaCl-776
$K^{+}$ -305	KCl-703
$C l^{-}$ -382

Maximum heat is absorbed in the dissolution of one mole of :

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Find the value of 703−1+1−400.