Find the value of a - b-in degrees- given that p - q and r - s-

Question

Toppr Admin · Accepted Answer

2a-x2218-80-x2218- -Corresponding angles -2a-x2218-80-x2218-x21D2-a-80-x2218-2-40-x2218-b-x2218-80-x2218-180-x2218- -Angles made on same side of transversal-x21D2-b-180-x2218-x2212-80-x2218-100-x2218-

Find the value of $a$ + $b$ (in degrees), given that $p | | q$ and $r | | s$ .

$2 a^{\circ} = 80^{\circ}$ (Corresponding angles )

$2 a^{\circ} = 80^{\circ}$

$\Rightarrow a = \frac{80^{\circ}}{2} = 40^{\circ}$

$b^{\circ} {+ 80}^{\circ} = 180^{\circ}$ (Angles made on same side of transversal)

$\Rightarrow b = 180^{\circ} - 80^{\circ} = 100^{\circ}$

Find the value of a + b(in degrees), given that p||q and r||s.

2a∘=80∘ (Corresponding angles )2a∘=80∘⇒a=80∘2=40∘b∘+80∘=180∘ (Angles made on same side of transversal)⇒b=180∘−80∘=100∘

Find the value of $a$ + $b$ (in degrees), given that $p | | q$ and $r | | s$ .

$2 a^{\circ} = 80^{\circ}$ (Corresponding angles )

$2 a^{\circ} = 80^{\circ}$

$\Rightarrow a = \frac{80^{\circ}}{2} = 40^{\circ}$

$b^{\circ} {+ 80}^{\circ} = 180^{\circ}$ (Angles made on same side of transversal)

$\Rightarrow b = 180^{\circ} - 80^{\circ} = 100^{\circ}$