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All India Test Series
Question
Find the value of x.
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Solution
Segment formed by intersecting secants
9
×
4
=
(
x
+
2
)
×
2
36
=
2
x
+
4
36
−
4
=
2
x
32
=
2
x
⇒
x
=
32
2
=
16
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Similar Questions
Q1
Find the value of x.
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Q2
(i) If
x
=
3
2
2
×
2
3
-
4
, find the value of x
−2
.
(ii) If
x
=
4
5
-
2
÷
1
4
2
, find the value of x
−1
.