Question

Find the value of ${\cos }^2{60}^{\circ }+{\sin }^2{30}^{\circ }$.

Answer 1

${\cos }^2{60}^{\circ }+{\sin }^2{30}^{\circ }$
$={\left(\frac{1}{2}\right)}^2+{\left(\frac{1}{2}\right)}^2$
$=\frac{1}{4}+\frac{1}{4}$
$=\frac{1}{2}$

$=0.5$