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Basic Trigonometric Identities

Question

Find the value of $c o s e c^{2} 60^{\circ} - {tan}^{2} 30^{\circ}$

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Solution

Verified by Toppr

${csc}^{2} 60^{\circ} - {tan}^{2} 30^{\circ}$
= $(\frac{2}{\sqrt{3}})^{2} - (\frac{1}{\sqrt{3}})^{2}$
= $\frac{4}{3} - \frac{1}{3}$
= $\frac{3}{3}$
= $1$

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