Question

Find the value of $\frac{\tan {45}^{\circ }}{cosec{30}^{\circ }}+\frac{\sec {60}^{\circ }}{\cot {45}^{\circ }}-\frac{5\sin {90}^{\circ }}{2\cos 0^{\circ }}$

Answer 1

we know that $\tan {45}^{\circ }=\cot {45}^{\circ }=\sin {90}^{\circ }=1,cosec{30}^{\circ }=\sec {60}^{\circ }=2,\cos 0^{\circ }=1$

$\frac{\tan {45}^{\circ }}{cosec{30}^{\circ }}+\frac{\sec {60}^{\circ }}{\cot {45}^{\circ }}-\frac{5\sin {90}^{\circ }}{2\cos 0^{\circ }}$

= $\frac{1}{2}+\frac{2}{1}-\frac{5\left(1\right)}{2\left(1\right)}$

= $\frac{1}{2}+\frac{2}{1}-\frac{5}{2}$

= $\frac{1+4-5}{2}$
= $0$