Find the weight of a solid cone whose base is of diameter $42 c m$ and vertical height $20 c m$ , supposing that the material of which it is made weights $5$ grams per cubic centimetre.

Question

Find the weight of a solid cone whose base is of diameter 14 cm and vertical height 51 cm- supporting the material of which it is made weighs 10 grams per cubic cm-

Toppr Admin · Accepted Answer

We have- -r-dfrac -diameter-2-7-cm- -h-51-cm-therefore- Weight -left-dfrac-1-3-times -dfrac-22-7-times 7-2-times 51-right-times -dfrac-10-1000-kg-26-180-kg-

Find the weight of a solid cone whose base is of diameter $$14$$ cm and vertical height $$51$$ cm, supporting the material of which it is made weighs $$10$$ grams per cubic cm.

We have, $$r=\dfrac {diameter}{2}=7$$cm, $$h=51$$cm

$$\therefore$$ Weight $$=\left(\dfrac{1}{3}\times \dfrac{22}{7}\times 7^2\times 51\right)\times \dfrac{10}{1000}$$kg$$=26.180$$kg.

Find the weight of a solid cone whose base is of diameter $$14$$ cm and vertical height $$51$$ cm, supporting the material of which it is made weighs $$10$$ grams per cubic cm.

We have, $$r=\dfrac {diameter}{2}=7$$cm, $$h=51$$cm$$\therefore$$ Weight $$=\left(\dfrac{1}{3}\times \dfrac{22}{7}\times 7^2\times 51\right)\times \dfrac{10}{1000}$$kg$$=26.180$$kg.

We have, $$r=\dfrac {diameter}{2}=7$$cm, $$h=51$$cm

$$\therefore$$ Weight $$=\left(\dfrac{1}{3}\times \dfrac{22}{7}\times 7^2\times 51\right)\times \dfrac{10}{1000}$$kg$$=26.180$$kg.