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Question

Find three rational numbers equivalent to
$$ \dfrac{4}{-7} $$

Solution
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$$ \dfrac{4}{-7} $$
It can be written as
$$ \dfrac{4}{-7} = \dfrac{4 \times 2}{-7 \times 2} = \dfrac{8}{-14} $$
$$ \dfrac{4}{-7} = \dfrac{4 \times 3}{-7 \times 3} = \dfrac{12}{-21} $$
$$ \dfrac{4}{-7} = \dfrac{4 \times 4}{-7 \times 4} = \dfrac{16}{-28} $$
Therefore , $$ \dfrac{8}{-14} , \dfrac{12}{-21} $$ and $$ \dfrac{16}{-28} $$ are the rational numbers which are equivalent to the given rational number $$ \dfrac{4}{-7} $$.

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