Find two consecutive natural numbers whose sum is $$63.$$
Let the required two consecutive natural numbers be $$x$$ and $$(x + 1)$$ Then,
$$ = x + (x + 1) = 63$$
$$ = x + x + 1 = 63$$
$$ = 2x + 1 = 63$$
Transporting $$1$$ to LHS and it becomes $$-1$$
$$ = 2x = 63 - 1$$
$$ = 2x = 62$$
Multiplying both sides by $$(1 / 2)$$
$$ = 2x \times (1 / 2) = 62 \times (1 / 2)$$
$$ = x = 31$$
The other number is $$(x + 1) = 31 + 1 = 32$$
$$\therefore$$ the required two consecutive natural numbers are $$31$$ and $$32$$