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Find value of 10x

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Given, $△ A B C$ , $∠ B = 90^{\circ}$ , $∠ A = 60$ and $B C = 20$
Now, $sin 60 = \frac{P}{H}$
$sin 60 = \frac{B C}{A C} = \frac{20}{x}$
$\frac{\sqrt{3}}{2} = \frac{20}{x}$
$x = \frac{40}{\sqrt{3}}$
$x = 23.1$

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