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Question

Find value of K
$$19 \times 12+19= 19\times (12+K)$$

A
$$1$$
B
$$3$$
C
$$2$$
D
$$-1$$
Solution
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Correct option is A. $$1$$
Let, the member is $$K$$
$$19 \times 12+19= 19\times (12+K)$$
$$228+19=19 \times 12+19 \times K$$
$$228+19=228 +19 \times K$$
$$19 \times K=228+19-228$$
$$19 \times K=19$$
$$K=\dfrac{\not{19}}{ \not{19}}=1$$

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