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Question

Find work done by gravity in moving the block from B to A

$- m g h$
$m g h$
$0$
$\frac{m g h}{2}$

A

\frac{m g h}{2}

B

m g h

C

0

D

- m g h

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Solution

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Here work is done along the gravity so the energy here is positive.
The potential energy can be written as $(W_{g})_{B t o A} = m g h$

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