Find x such that - dfrac-2-3- - dfrac-6-x-

Question

Toppr Admin · Accepted Answer

- -dfrac-2-3- - -dfrac-6-x- -160-By cross mulriplication-160- -2x - 6 -times 3 -160-By further calculation- x - -dfrac-6 -times 3-2- -160-So we get-160- x - -dfrac-18-2- - -9 -160-Hence - - -dfrac-2-3- - -dfrac-6-9- -160-

Find $$x$$ such that :
$$ \dfrac{-2}{3} = \dfrac{6}{x} $$

$$ \dfrac{-2}{3} = \dfrac{6}{x} $$
By cross mulriplication
$$ -2x = 6 \times 3 $$
By further calculation
$$ x = \dfrac{6 \times 3}{-2} $$
So we get
$$ x = \dfrac{18}{-2} = -9 $$
Hence , $$ \dfrac{-2}{3} = \dfrac{6}{-9} $$

Find $$x$$ such that :$$ \dfrac{-2}{3} = \dfrac{6}{x} $$

$$ \dfrac{-2}{3} = \dfrac{6}{x} $$ By cross mulriplication $$ -2x = 6 \times 3 $$ By further calculation$$ x = \dfrac{6 \times 3}{-2} $$ So we get $$ x = \dfrac{18}{-2} = -9 $$ Hence , $$ \dfrac{-2}{3} = \dfrac{6}{-9} $$

Find $$x$$ such that :
$$ \dfrac{-2}{3} = \dfrac{6}{x} $$

$$ \dfrac{-2}{3} = \dfrac{6}{x} $$
By cross mulriplication
$$ -2x = 6 \times 3 $$
By further calculation
$$ x = \dfrac{6 \times 3}{-2} $$
So we get
$$ x = \dfrac{18}{-2} = -9 $$
Hence , $$ \dfrac{-2}{3} = \dfrac{6}{-9} $$