Find x - such that - dfrac-7-4- - dfrac-x-8-

Question

Toppr Admin · Accepted Answer

- -dfrac-7-4- - -dfrac-x-8- -160-By cross multiplication-160- 7 -times 8 - -4 -times x -160-On further calculation-160- 56 - -4x -160-So we get-160- x - -dfrac-56-4- - -14 -160-Hence- - -dfrac-7-4- - -dfrac-14-8- -

Find $$x$$ , such that :
$$ \dfrac{7}{-4} = \dfrac{x}{8} $$

$$ \dfrac{7}{-4} = \dfrac{x}{8} $$
By cross multiplication
$$ 7 \times 8 = -4 \times x $$
On further calculation
$$ 56 = -4x $$
So we get
$$ x = \dfrac{56}{-4} = -14 $$
Hence, $$ \dfrac{7}{-4} = \dfrac{-14}{8} $$.

Find $$x$$ , such that :$$ \dfrac{7}{-4} = \dfrac{x}{8} $$

$$ \dfrac{7}{-4} = \dfrac{x}{8} $$ By cross multiplication $$ 7 \times 8 = -4 \times x $$ On further calculation $$ 56 = -4x $$ So we get $$ x = \dfrac{56}{-4} = -14 $$ Hence, $$ \dfrac{7}{-4} = \dfrac{-14}{8} $$.

Find $$x$$ , such that :
$$ \dfrac{7}{-4} = \dfrac{x}{8} $$

$$ \dfrac{7}{-4} = \dfrac{x}{8} $$
By cross multiplication
$$ 7 \times 8 = -4 \times x $$
On further calculation
$$ 56 = -4x $$
So we get
$$ x = \dfrac{56}{-4} = -14 $$
Hence, $$ \dfrac{7}{-4} = \dfrac{-14}{8} $$.