Find $$e^{2.1}$$, approximately given $$e^{2}$$ = 7.389

Open in App

Solution

Verified by Toppr

Was this answer helpful?

Similar Questions

e^{2.1}

given

e^{2} = 7.389

View Solution

$A \to A^{+} e, E_{1} a n d A^{+} \to A^{2 +} + e, E_{2}$ .
1. The energy required to pull out the two electrons are $E_{1}$ and $E_{2}$ respectively. The correct relationship between two energy would be

View Solution

Subtract:
$7.389$ from $10$

View Solution

The ratio of

(E_{2} - E_{1})

(E_{4} - E_{3})

for

H

- atom is approximately.

View Solution

The ratio of

(E_{2} - E_{1})

(E_{4} - E_{3})

for the hydrogen atom is approximately equal to:

View Solution