Follow data is given for the reaction: CaCO3⇌CaO(s)+CO2(g) ΔfH⊖[CaO(s)]=−635.1kJmol−1 ΔfH⊖[CO2(g)]=−393.5kJmol−1 ΔfH⊖[CaCO3(s)]=−1206.9kJmol−1 Predict the effect of temperature on the equilibrium constant of the above reaction.
If T increases, reaction proceeds in forward direction.
If T increases, reaction proceeds in backward direction.
If T decreases, reaction proceeds in forward direction.
If T increases, reaction remains at equilibrium.
A
If T increases, reaction proceeds in forward direction.
B
If T increases, reaction remains at equilibrium.
C
If T increases, reaction proceeds in backward direction.
D
If T decreases, reaction proceeds in forward direction.
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Solution
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ΔrH⊖=ΔrH⊖[CaO(s)]+ΔrH⊖[CO2(9)]−ΔrH⊖[CaCO3(s)] ∴ΔrH⊖=178.3kJmol−1 The reaction is endothermic. Hence, according to Le-Chatelier's principle, reaction will proceed in forward direction on increasing temperature.
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