For a particle executing SHM having amplitude 'a' the speed of the particle is one half of its maximum speed when its displacement from the mean position is
$a / 2$
a
$a \frac{\sqrt{3}}{2}$
2a

Question

For a particle executing SHM having amplitude -a- the speed of the particle is one half of its maximum speed when its displacement from the mean position isa-2aafrac-sqrt-3-2-2a

Toppr Admin · Accepted Answer

-x-Asin-x3C9-t-x21D2-dxdt-A-x3C9-cos-x3C9-t-x21D2-v-A-x3C9-cos-x3C9-t

For a particle executing SHM having amplitude 'a' the speed of the particle is one half of its maximum speed when its displacement from the mean position isa/2aa√322a

x=Asinωt⇒dxdt=Aωcosωt⇒v=Aωcosωt

For a particle executing SHM having amplitude 'a' the speed of the particle is one half of its maximum speed when its displacement from the mean position is
$a / 2$
a
$a \frac{\sqrt{3}}{2}$
2a

$x = A sin ω t \Rightarrow \frac{d x}{d t} = A ω cos ω t \Rightarrow v = A ω cos ω t$