For a prism kept in air, it is found that for an angle of incidence 60∘, the angle of refraction ′A′, angle of deviation ′δ′, and angle of emergence ′e′ become equal. The minimum angle of incidence of a ray that will be transmitted through the prism is
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Updated on : 2022-09-05
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Correct option is A)
Given i=60∘,A=δ=e δ=i+e−A⇒δ=1 (∵e=A) and (δ=i=e μ=sin2Asin(2A+δm) Here, angle of deviation is minimum (∵i=e) μ=sin(60∘/2)sin(260∘+60∘)=3.