For a prism kept in air, it is found that for an angle of incidence 60∘, the angle of refraction ′A′, angle of deviation ′δ′ and angle of emergence ′e′ become equal. Then, the refractive index of the prism is
1.73
1.15
1.5
1.33
A
1.15
B
1.33
C
1.5
D
1.73
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Solution
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Given i=60∘A=δ=e δ=i+e−A⇒δ=1(∵e=A) μ=sin(A+δm2)sinA2 Here, angle of deviation is minimum (∵i=e) μ=sin(60∘+60∘2)sin(60∘/2)=1.73.
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(a) A ray 'PQ' of light is incident on the face AB of a glass prism ABC (as shown in the figure) and emerges out of the face AC. Trace the path of the ray. Show that ∠i+∠e=∠A+∠δ. When δ and e denote the angle of deviation and angle of emergence respectively.
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