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Question

For a prism kept in air, it is found that for an angle of incidence 60, the angle of refraction A, angle of deviation δ and angle of emergence e become equal. Then, the refractive index of the prism is
  1. 1.73
  2. 1.15
  3. 1.5
  4. 1.33

A
1.15
B
1.33
C
1.5
D
1.73
Solution
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Given i=60A=δ=e
δ=i+eAδ=1(e=A)
μ=sin(A+δm2)sinA2
Here, angle of deviation is minimum (i=e)
μ=sin(60+602)sin(60/2)=1.73.

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