For a radioactive material- half-life is 10 minutes- If initially there are 600 number of nuclei- the time taken -in minutes- the disintegration of 450 nuclei is-30201510

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Toppr Admin · Accepted Answer

Half life -10min-ln2-x3BB-Nuclei disintegrate - 450Nuclei left - 600-450 -150N-Noe-x2212-x3BB-t150-600e-x2212-ln210tso- t - 20 minutes

For a radioactive material, half-life is $10$ minutes. If initially there are $600$ number of nuclei, the time taken (in minutes) for the disintegration of $450$ nuclei is?
$30$
$20$
$15$
$10$

Half life $= 10 m i n = \frac{l n 2}{λ}$
Nuclei disintegrate = 450
Nuclei left = 600-450 =150
$N = N_{o} e^{- λ} t$
$150 = 600 e^{\frac{- l n 2}{10} t}$
so, t = 20 minutes

For a radioactive material, half-life is 10 minutes. If initially there are 600 number of nuclei, the time taken (in minutes) for the disintegration of 450 nuclei is?30201510

Half life =10min=ln2λNuclei disintegrate = 450Nuclei left = 600-450 =150N=Noe−λt150=600e−ln210tso, t = 20 minutes

For a radioactive material, half-life is $10$ minutes. If initially there are $600$ number of nuclei, the time taken (in minutes) for the disintegration of $450$ nuclei is?
$30$
$20$
$15$
$10$

Half life $= 10 m i n = \frac{l n 2}{λ}$
Nuclei disintegrate = 450
Nuclei left = 600-450 =150
$N = N_{o} e^{- λ} t$
$150 = 600 e^{\frac{- l n 2}{10} t}$
so, t = 20 minutes