For a reaction in a galvanic cell- the value of -triangle G-smallcirc- certain temperature is not necessarily equal to-nFE-smallcirc-RTspace lnspace KTtriangle S-smallcirc- - triangle H-smallcirc-text zero

Question

Toppr Admin · Accepted Answer

As we know-x394-G0-x2212-nFE0- so it cannot be necessarily zero except H-electrode-Also-x394-G0-x394-H0-x2212-T-x394-S0 andAt equilibrium-x394-G0-x2212-RTlnKTherefore- it is not necessarily equal to zero-Option D is correct-

For a reaction in a galvanic cell, the value of $- △ G^{\circ}$ at certain temperature is not necessarily equal to:
$n F E^{\circ}$
$R T l n K$
$T △ S^{\circ} - △ H^{\circ}$
$z e r o$

As we know,
$Δ G^{0} = - n F E^{0}$ , so it cannot be necessarily zero except H-electrode.

Also,
$Δ G^{0} = Δ H^{0} - T Δ S^{0}$ and

At equilibrium,
$Δ G^{0} = - R T l n K$

Therefore, it is not necessarily equal to zero.

Option D is correct.

For a reaction in a galvanic cell, the value of −△G∘ at certain temperature is not necessarily equal to:nFE∘RT ln KT△S∘−△H∘zero

As we know,ΔG0=−nFE0, so it cannot be necessarily zero except H-electrode.Also,ΔG0=ΔH0−TΔS0 andAt equilibrium,ΔG0=−RTlnKTherefore, it is not necessarily equal to zero.Option D is correct.

For a reaction in a galvanic cell, the value of $- △ G^{\circ}$ at certain temperature is not necessarily equal to:
$n F E^{\circ}$
$R T l n K$
$T △ S^{\circ} - △ H^{\circ}$
$z e r o$

As we know,
$Δ G^{0} = - n F E^{0}$ , so it cannot be necessarily zero except H-electrode.

Also,
$Δ G^{0} = Δ H^{0} - T Δ S^{0}$ and

At equilibrium,
$Δ G^{0} = - R T l n K$

Therefore, it is not necessarily equal to zero.

Option D is correct.