For a solution containing a non-volatile solute, the relative lowering of vapour pressure is 0.2. If the solution contains 5 moles in all, then the number of moles of solvent in the solution is:

Question

For a solution containing a non-volatile solute- the relative lowering of vapour pressure is 0-2- If the solution contains 5 moles in all- then the number of moles of solvent in the solution is-4352

Toppr Admin · Accepted Answer

-x394-PP0-XsoluteXsolute-0-x22C5-2nsolutentotal-0-x22C5-2nsolute-0-x22C5-2-xD7-5-xA0-mol-1-xA0-molThen nsolvent-5-x2212-1-4-xA0-molesHence- the correct option is A

For a solution containing a non-volatile solute, the relative lowering of vapour pressure is 0.2. If the solution contains 5 moles in all, then the number of moles of solvent in the solution is:
$4$
$3$
$5$
$2$

$\frac{Δ P}{P_{0}} = X_{s o l u t e}$

$X_{s o l u t e} = 0 \cdot 2$

$\frac{n_{s o l u t e}}{n_{t o t a l}} = 0 \cdot 2$

$n_{s o l u t e} = 0 \cdot 2 \times 5 m o l = 1 m o l$

Then $n_{s o l v e n t} = 5 - 1 = 4 m o l e s$

Hence, the correct option is $A$

For a solution containing a non-volatile solute, the relative lowering of vapour pressure is 0.2. If the solution contains 5 moles in all, then the number of moles of solvent in the solution is:4352

ΔPP0=XsoluteXsolute=0⋅2nsolutentotal=0⋅2nsolute=0⋅2×5 mol=1 molThen nsolvent=5−1=4 molesHence, the correct option is A

For a solution containing a non-volatile solute, the relative lowering of vapour pressure is 0.2. If the solution contains 5 moles in all, then the number of moles of solvent in the solution is:
$4$
$3$
$5$
$2$

$\frac{Δ P}{P_{0}} = X_{s o l u t e}$

$X_{s o l u t e} = 0 \cdot 2$

$\frac{n_{s o l u t e}}{n_{t o t a l}} = 0 \cdot 2$

$n_{s o l u t e} = 0 \cdot 2 \times 5 m o l = 1 m o l$

Then $n_{s o l v e n t} = 5 - 1 = 4 m o l e s$

Hence, the correct option is $A$