For a spontaneous reaction the Delta G- equilibrium constant K and E-0-cell- will be respectively-ve- - 1- -ve-ve- 1- -ve-ve- - 1- -ve

Question

For a spontaneous reaction the Delta G- equilibrium constant K and E-0-cell- will be respectively-ve- - 1- -ve-ve-  1- -ve-ve- - 1- -ve

Toppr Admin · Accepted Answer

We know-xA0- -x394-G-x2212-RTlnK-x2212-nFE-x2218-We know-xA0-for a spontaneous reaction-x394-G-lt-0-x2234-x2212-RTlnK-lt-0-x2234-lnK-gt-0-x2234-K-gt-1and-xA0- -x2212-nFE-x2218-lt-0-x2234-E-x2218-cell-gt-0

For a spontaneous reaction the $Δ G$ , equilibrium constant $K$ and $E {^{0}}_{c e l l}$ will be respectively:

$- v e, > 1, - v e$
$- v e, < 1, - v e$
$+ v e, > 1, - v e$
$- v e, > 1, + v e$

we know $Δ G = - R T l n K = - n F E^{\circ}$
We know for a spontaneous reaction
$Δ G < 0$ .

$∴ - R T l n K < 0$

$∴ l n K > 0$

$∴ K > 1$

and $- n F E^{\circ} < 0$

$∴ E_{c e l l}^{\circ} > 0$

For a spontaneous reaction the ΔG, equilibrium constant K and E0cell will be respectively:−ve,>1,−ve−ve,<1,−ve+ve,>1,−ve−ve,>1,+ve

we know ΔG=−RTlnK=−nFE∘We know for a spontaneous reactionΔG<0.∴−RTlnK<0∴lnK>0∴K>1and −nFE∘<0∴E∘cell>0

For a spontaneous reaction the $Δ G$ , equilibrium constant $K$ and $E {^{0}}_{c e l l}$ will be respectively:

$- v e, > 1, - v e$
$- v e, < 1, - v e$
$+ v e, > 1, - v e$
$- v e, > 1, + v e$

we know $Δ G = - R T l n K = - n F E^{\circ}$
We know for a spontaneous reaction
$Δ G < 0$ .

$∴ - R T l n K < 0$

$∴ l n K > 0$

$∴ K > 1$

and $- n F E^{\circ} < 0$

$∴ E_{c e l l}^{\circ} > 0$