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Question

For a triangle ABC, which of the following is true?
${B C}^{2} - {A B}^{2} = {A C}^{2}$
$A B - A C = B C$
$(A B - A C) > B C$
$A B - A C < B C$

A

A B - A C = B C

B

(A B - A C) > B C

C

A B - A C < B C

D

{B C}^{2} - {A B}^{2} = {A C}^{2}

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Solution

Verified by Toppr

For any $△ A B C$ ,
the difference between two sides of the triangle should be less than the third side.
Thus, $A B - A C < B C$

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