For an adiabatic processdisplaystyle Delta S-0displaystyle Q-0displaystyle W-0displaystyle Delta U-0

Question

Toppr Admin · Accepted Answer

During an adiabatic process- there is no exchange of energy between system and its surrounding-Thus- -x394-Q-0Thus- the entropy also does not change- and -x394-S-0

For an adiabatic process
$Δ S = 0$
$Q = 0$
$W = 0$
$Δ U = 0$

During an adiabatic process, there is no exchange of energy between system and its surrounding.
Thus, $Δ Q = 0$
Thus, the entropy also does not change, and $Δ S = 0$

For an adiabatic processΔS=0Q=0W=0ΔU=0

During an adiabatic process, there is no exchange of energy between system and its surrounding.Thus, ΔQ=0Thus, the entropy also does not change, and ΔS=0

For an adiabatic process
$Δ S = 0$
$Q = 0$
$W = 0$
$Δ U = 0$

During an adiabatic process, there is no exchange of energy between system and its surrounding.
Thus, $Δ Q = 0$
Thus, the entropy also does not change, and $Δ S = 0$