For any two complex numbers z1 and z2, prove that Re(z1z2)=Rez1Rez2−Imz1Imz2
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Solution
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Let z1=x1+iy1 and z2=x2+iy2 ⇒z1z2=(x1+iy1)(x2+iy2) =x1x2+i(y1x2+x1y2)+i2y1y2 =(x1x2−y1y2)+i(y1x2+x1y2), since (i2=−1) Hence Re(z1z2)=Re(z1)Re(z2)−Im(z1)Im(z2)
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