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Question

For any two non-zero rational numbers $$z, (z^{-2})^{3} $$ is equal to

A
$$z^{1}$$
B
$$z^{4}$$
C
$$z^{-6}$$
D
$$z^{6}$$
Solution
Verified by Toppr

Correct option is B. $$z^{-6}$$
Using law of exponents, $$(a^m)^n =(a)^{mn}$$
Therefore, $$(z^{-2})^3 =(z)^{-2\times 3}=(z)^{-6}$$

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