For CE transistor amplifier- the audio signal voltage across the collector resistance of 2 kOmega is 4 V- If the current amplification factor of the transistor is 100 and the base resistance is 1 kOmega- then the input signal voltage is20 mV10 mV5 mV30 mV

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Toppr Admin · Accepted Answer

Given that- I-x3B1-I-x3B2-100-RB-1000-x3A9-x21D2-x3B2-100-I-x3B1-I-x3B2-x21D2-V0-4V-x21D2-V0Vi-x3B2-RLRB-x21D2-Vi-4-xD7-1000100-xD7-2000-0-02-20-xA0-mV

For CE transistor amplifier, the audio signal voltage across the collector resistance of $2 k Ω$ is $4 V$ . If the current amplification factor of the transistor is $100$ and the base resistance is $1 k Ω$ , then the input signal voltage is
$20 m V$
$10 m V$
$5 m V$
$30 m V$

Given that: $\frac{I_{α}}{I_{β}} = 100; R_{B} = 1000 Ω$

$\Rightarrow β = 100 = \frac{I_{α}}{I_{β}}$

$\Rightarrow V_{0} = 4 V$

$\Rightarrow \frac{V_{0}}{V_{i}} = β \frac{R_{L}}{R_{B}}$

$\Rightarrow V_{i} = \frac{4 \times 1000}{100 \times 2000} = 0.02 = 20 m V$

For CE transistor amplifier, the audio signal voltage across the collector resistance of 2kΩ is 4V. If the current amplification factor of the transistor is 100 and the base resistance is 1kΩ, then the input signal voltage is20mV10mV5mV30mV

Given that: IαIβ=100;RB=1000Ω⇒β=100=IαIβ⇒V0=4V⇒V0Vi=βRLRB⇒Vi=4×1000100×2000=0.02=20 mV

For CE transistor amplifier, the audio signal voltage across the collector resistance of $2 k Ω$ is $4 V$ . If the current amplification factor of the transistor is $100$ and the base resistance is $1 k Ω$ , then the input signal voltage is
$20 m V$
$10 m V$
$5 m V$
$30 m V$

Given that: $\frac{I_{α}}{I_{β}} = 100; R_{B} = 1000 Ω$

$\Rightarrow β = 100 = \frac{I_{α}}{I_{β}}$

$\Rightarrow V_{0} = 4 V$

$\Rightarrow \frac{V_{0}}{V_{i}} = β \frac{R_{L}}{R_{B}}$

$\Rightarrow V_{i} = \frac{4 \times 1000}{100 \times 2000} = 0.02 = 20 m V$