Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

for fride \( f ( x ) = \) 53 \( \cos ^ { - 1 } \frac { ( 2 n - 1 ) } { 5 } \) \( \left( x ^ { 2 } + x ^ { 2 } + 1 \right) \) \( - 16 ^ { 2 } - 5 b + 4 \) 1.5 \( B \) \( . \)

Open in App

Solution

Verified by Toppr

Was this answer helpful?

0

Similar Questions

Q1

Assertion :Let

f (x) = c o t^{- 1} (\frac{3 x - x^{3}}{1 - 3 x^{2}}), g (x) = c o s^{- 1} (\frac{1 - x^{2}}{1 + x^{2}})

then

f (x) = g (x)

if

x = \frac{\sqrt{25 - 10 \sqrt{5}}}{5}

. Reason:

s i n 18^{o} = \frac{\sqrt{5} - 1}{4}

.

View Solution

Q2

If

g (x)

is shifted

1

unit left of

f (x) = x^{2} - 6,

then

g (x)

is

View Solution

Q3

Let

f (x) = c o s^{- 1} (\frac{1 - x^{2}}{1 + x^{2}}) + t a n^{- 1} (\frac{2 x}{1 - x^{2}})

where

x \in (- 1, 0)

then f(x) is equal to

View Solution

Q4

If

f (x) = {cos}^{- 1} {\frac{1 - {({log}_{e} x)}^{2}}{1 + {({log}_{e} x)}^{2}}}

, then

f^{'} (e)

View Solution

Q5

Assertion :If

f (x) = {cos}^{- 1} (\frac{2 x}{1 + x^{2}})

, then

f (x)

is differentiable everywhere Reason: For

f (x) = {cos}^{- 1} (\frac{2 x}{1 + x^{2}})

,

f^{'} (x) = ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \begin{matrix} \frac{- 2}{1 + x^{2}}, & | x | < 1 \end{matrix} \begin{matrix} \frac{2}{1 + x^{2}}, & | x | > 1 \end{matrix} \end{matrix}

View Solution