For the cell M- M- - X- X- E-circ-M- M- - 0-44 and E-X- X-circ- - 0-33 V- From the data it can be deduced that M - Xrightarrow M- - X- is spontaneous-E-Cell- - -0-77 VNoneM - Xrightarrow M- - X- is spontaneousE-Cell- - 0-77 V

Question

Toppr Admin · Accepted Answer

For a reaction to be spantaneous-Ere should be positiveHence-xA0-E0M-M-x2212-E0X-X-x2212-0-44-x2212-0-33-0-11As-xA0-EM-X-x2212- is positive- We can conclude that-xA0-M-X-x2212-x2192-M-X-x2212- is Spantaneous as-xA0-Ecell is 0-11V-

For the cell $M / M^{+} | | X^{-} / X, E_{M^{+} / M}^{\circ} = 0.44$ and $E_{X / X^{-}}^{\circ} = 0.33 V$ . From the data it can be deduced that $M + X \to M^{+} + X^{-}$ is spontaneous.
$E_{C e l l} = - 0.77 V$
None
$M + X \to M^{+} + X^{-}$ is spontaneous
$E_{C e l l} = 0.77 V$

For a reaction to be spantaneous,
$E_{r e}$ should be positive
Hence ${E^{0}}_{M^{+} / M} {- E}^{0}_{X / X^{-}} = 0.44 - 0.33 = 0.11$
As $E_{M^{+} / X^{-}}$ is positive. We can conclude that $M^{+} + X^{-} \to M^{+} + X^{-}$ is Spantaneous as $E_{c e l l}$ is $0.11 V$ .

For the cell M/M+||X−/X,E∘M+/M=0.44 and E∘X/X−=0.33 V. From the data it can be deduced that M+X→M++X− is spontaneous.ECell=−0.77 VNoneM+X→M++X− is spontaneousECell=0.77 V

For a reaction to be spantaneous,Ere should be positiveHence E0M+/M−E0X/X−=0.44−0.33=0.11As EM+/X− is positive. We can conclude that M++X−→M++X− is Spantaneous as Ecell is 0.11V.

For the cell $M / M^{+} | | X^{-} / X, E_{M^{+} / M}^{\circ} = 0.44$ and $E_{X / X^{-}}^{\circ} = 0.33 V$ . From the data it can be deduced that $M + X \to M^{+} + X^{-}$ is spontaneous.
$E_{C e l l} = - 0.77 V$
None
$M + X \to M^{+} + X^{-}$ is spontaneous
$E_{C e l l} = 0.77 V$

For a reaction to be spantaneous,
$E_{r e}$ should be positive
Hence ${E^{0}}_{M^{+} / M} {- E}^{0}_{X / X^{-}} = 0.44 - 0.33 = 0.11$
As $E_{M^{+} / X^{-}}$ is positive. We can conclude that $M^{+} + X^{-} \to M^{+} + X^{-}$ is Spantaneous as $E_{c e l l}$ is $0.11 V$ .