for the cell reaction
$$Cu^{2+}(C_1aq)+Zn(s)=Zn^{2+}(C_2aq)+Cu(s)$$
of an electrochemical cell, the change in free energy at a given temperature is a function of
Correct option is D. $$\ln (C_2 /C_1)$$
Answer is option (D)
We know
$$ΔG=nFE$$
Again according to Nernst equation,
$$E=\dfrac{0.059}{n}$$ $$log \dfrac{[Zn^{2+} ]}{[Cu^{2+} ]}$$ $$ at $$25^o$$ C.
So $$ΔG$$ (free energy change) in an electrochemical cell at a given temperature is a function of
ln $$\dfrac{[Zn^{2+} ]}{ [Cu^{2+}]}$$ $$=ln\dfrac{C_2}{C_1}$$