For the circuit show below, the current through the zener diode is :

Question

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Answer 1

Assuming zener diode does not undergo breakdown, current in circuit = $\frac{1 2 0}{1 5 0 0 0} = 8 m A$
Voltage drop across diode = 80 V > 50 V. The diode undergo breakdown.
Current is $R_{1} = \frac{7 0}{5 0 0 0} = 14 m A$
Current is $R_{2} = \frac{5 0}{1 0 0 0 0} = 5 A$
current through diode = 9 mA

Answer 2

Assuming zener diode does not undergo breakdown, current in circuit =

\frac{1 2 0}{1 5 0 0 0} = 8 m A

Voltage drop across diode = 80 V > 50 V. The diode undergo breakdown.
Current is

R_{1} = \frac{7 0}{5 0 0 0} = 14 m A

Current is

R_{2} = \frac{5 0}{1 0 0 0 0} = 5 A

current through diode = 9 mA