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Question

For the equilibrium: $$ SrCl_2. 6H_2O(s) \rightleftharpoons SrCl_2.2H_2O(s) + 4H_2O(g), K_p=8.1 \times 10^{-7} atm^4\ at \ 27^oC $$. If 1.642L of air saturated with water vapour at $$ 27^oC $$ is exposed to a large quantity of of $$SrCl_2.2H_2O(s)$$, what weight of water vapour will be absored ? Saturated vapour pressure of water at $$ 27^oC=30.4 $$ torr.

A
12 mg
B
9 mg
C
48 mg
D
6.67 mg
Solution
Verified by Toppr

Correct option is A. 12 mg

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Q1
For the equilibrium:

SrCl2.6H2O(s)SrCl2.2H2O(s)+4H2O(g)

the equilibrium constant Kp = 16 x 1012 atm4 at 1oC. If one litre of air saturated with water vapour at 1 oC is exposed to a large quantity of SrCl2.2H2O(s), what weight of water vapour will be absorbed? Saturated vapour pressure of water at 1oC a 7.6 torr.

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Q2
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Q3

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Q4
For the equilibrium SrCl26H2O(s)SrCl22H2O(s)+4H2O(g) the equilibrium constant Kp=16×1012 atm4 at 10C.

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For the equilibrium SrCl26H2O(s)SrCl22H2O(s)+4H2O(g) the equilibrium constant KP=16×1012atm4 at 1C. If one litre of air saturated with water vapour at 1C is exposed to a large quantity of SrCl22H2O(s), what weight of water vapour will be absorbed? Saturated vapour pressure of water at 1C=7.6 torr.
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