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Standard XII
Chemistry
Question

For the fuel cell reaction : 2H2(g)+O2(g)→2H2O(l);ΔfH∘298(H2O,l)=−285.5 kJ/mol what is ΔS0298 for the given fuel cell reaction?
Given: O2(g)+4H+(aq)+4e−→2H2O(l);E∘=1.23V

  1. 0.322kJ/K
  2. −0.635kJ/K
  3. 3.51kJ/K
  4. −0.322kJ/K

A
0.322kJ/K
B
3.51kJ/K
C
−0.322kJ/K
D
−0.635kJ/K
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Q1
For the fuel cell reaction : 2H2(g)+O2(g)→2H2O(l);ΔfH∘298(H2O,l)=−285.5 kJ/mol what is ΔS0298 for the given fuel cell reaction?
Given: O2(g)+4H+(aq)+4e−→2H2O(l);E∘=1.23V

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Q2
For the fuel cell reaction 2H2(g)+O2(g)⟶2H2(l);△fHo298(H2O,l)=−285.5 kJ/mol What is ΔS0298 for the give n fuel cell reaction?
Given : O2(g)+4H+(aq)+4e−⟶2H2O(l) Eo=1.23V
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Q3
Given the fuel cell reaction:
2H2(g)+O2(g)→2H2O(l);

ΔfHo298(H2O,l)=−285.5 kJ/mol

What is ΔSo298 for the given fuel cell reaction?

[Given: O2(g)+4H+(aq)+4e−→2H2O(l); Eo=1.23 V]

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Q4
For a cell reaction 2H2(g)+O2(g)⟶2H2O(l) ;△rS∘298=−0.32 kJ/K. What is the value of △fH∘298(H2O, l)?
Given O2(g)+4H+(aq.)+4e−⟶2H2O(l);E∘=1.23 V
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Q5
For a cell reaction,
2H2(g)+O2(g)→2H2O(l) △S0298=−0.32 kJK−1. What is the value of △fH0298(H20,l)
Given : O2(g)+4H+(aq)+4e−→2H20(l); E0=1.23V
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