For the galvanic cell : $$Ag\left | AgCl(s)\left | KCl(0.2\:M) \right | \right | KBr(0.001\:M)\left | AgBr(s) \right |Ag$$,Calculate the EMF in V, generated and assign correct polarity to each electrode for a spontaneous process after taking into account the cell reaction at $$25^{\circ}C$$.
$$\left [ K_{sp}=2.8\times 10^{-10}; K_{sp(AgBr)}=3.3\times 10^{-13} \right ]$$