For the given circuit shown in figure, the potential of the battery is varied from $$10V$$ to $$16V$$. If by zener diode breakdown voltage is $$6V$$, find maximum current through zener diode.
A
$$1.5\ mA$$
B
$$5\ mA$$
C
$$3.5\ mA$$
D
$$6.5\ mA$$
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Solution
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Correct option is B. $$3.5\ mA$$ $$i_{i} = \dfrac {6}{4} = 1.5\ mA$$ Maximum current will be obtained for battery voltage $$16\ V$$ $$i = \dfrac {16 - 6}{2} = 5mA\ i_{z}(max) = 5 - 1.5 = 3.5\ mA$$.
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