For the given combination of gates- the logic states of inputs A- B- C are as follows A - B - C - 0 and A- B - 1- C - 0 then the logic states of output D are0- 00- 11- 01- 1

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Toppr Admin · Accepted Answer

The output D for the given combination-D-xAF-A-B-C-xAF-A-B-CIf A-B-C-0 then D-xAF-0-0-xAF-0-xAF-0-xAF-0-1-1-1if -B-1-C-0 then D-xAF-1-1-xAF-0-xAF-1-xAF-0-0-1-1

For the given combination of gates, if the logic states of inputs A, B, C are as follows $A = B = C = 0$ and $A = B = 1, C = 0$ then the logic states of output D are

$0, 0$
$0, 1$
$1, 0$
$1, 1$

The output D for the given combination:
$D = ¯ (A + B) . C = ¯ (A + B) + C$
If $A = B = C = 0$ then $D = (¯ 0 + 0) + ¯ 0 = ¯ 0 + ¯ 0 = 1 + 1 = 1$
if $= B = 1, C = 0$ then $D = (¯ 1 + 1) + ¯ 0 = ¯ 1 + ¯ 0 = 0 + 1 = 1$

For the given combination of gates, if the logic states of inputs A, B, C are as follows A=B=C=0 and A=B=1,C=0 then the logic states of output D are0,00,11,01,1

The output D for the given combination:D=¯(A+B).C=¯(A+B)+CIf A=B=C=0 then D=(¯0+0)+¯0=¯0+¯0=1+1=1if =B=1,C=0 then D=(¯1+1)+¯0=¯1+¯0=0+1=1

For the given combination of gates, if the logic states of inputs A, B, C are as follows $A = B = C = 0$ and $A = B = 1, C = 0$ then the logic states of output D are

$0, 0$
$0, 1$
$1, 0$
$1, 1$

The output D for the given combination:
$D = ¯ (A + B) . C = ¯ (A + B) + C$
If $A = B = C = 0$ then $D = (¯ 0 + 0) + ¯ 0 = ¯ 0 + ¯ 0 = 1 + 1 = 1$
if $= B = 1, C = 0$ then $D = (¯ 1 + 1) + ¯ 0 = ¯ 1 + ¯ 0 = 0 + 1 = 1$