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Question

For the given incident ray as shown in figure, the condition of total internal reflection of this ray the minimum refractive index of prism will be :
69266_3bbcb1c9dc1b413582c71d731c730956.png
  1. 3+12
  2. 2+12
  3. 32
  4. 76

A
32
B
3+12
C
76
D
2+12
Solution
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For critical reflection

sinθc=1μ

cosθc=1sin2θc=11μ2

μcosθc=μ21 ........ (1)

Applying Snell’s law at first incident

μosinθi=μsinθr

1×sin45o=μsin(90θc)

12=μcosθc=μ21

μ=32


1000049_69266_ans_68108aa89f2c42398cafd4d214b389e8.png

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