For the hydrogen atom- the energy of the electron in the nth orbit is given by E-dfrac-13-6-n-2- eV- where n is an integer- The smallest amount of energy that a hydrogen atom can absorb in its ground state is-1-00- eV3-4 -eV6-8-eV10-2 -eV

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Toppr Admin · Accepted Answer

Minimumenergy-x21D2-n-2ton-1-xA0-Energy of the 2nd orbit -x2212-3-4ev-xA0-xA0- -xA0- -x394-E-10-2ev

For the hydrogen atom, the energy of the electron in the $n$ th orbit is given by $E = \frac{- 13.6}{n^{2}} e V$ , where $n$ is an integer. The smallest amount of energy that a hydrogen atom can absorb in its ground state is:
$1.00 e V$
$3.4 e V$
$6.8 e V$
$10.2 e V$

$m i n i m u m e n e r g y \Rightarrow n = 2 t o n = 1$
Energy of the $2^{n d}$ orbit $= - 3.4 e v$
$Δ E = 10.2 e v$

For the hydrogen atom, the energy of the electron in the nth orbit is given by E=−13.6n2 eV, where n is an integer. The smallest amount of energy that a hydrogen atom can absorb in its ground state is:1.00eV3.4eV6.8eV10.2eV

minimumenergy⇒n=2ton=1 Energy of the 2nd orbit =−3.4ev ΔE=10.2ev

For the hydrogen atom, the energy of the electron in the $n$ th orbit is given by $E = \frac{- 13.6}{n^{2}} e V$ , where $n$ is an integer. The smallest amount of energy that a hydrogen atom can absorb in its ground state is:
$1.00 e V$
$3.4 e V$
$6.8 e V$
$10.2 e V$

$m i n i m u m e n e r g y \Rightarrow n = 2 t o n = 1$
Energy of the $2^{n d}$ orbit $= - 3.4 e v$
$Δ E = 10.2 e v$