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Question

For the logic circuit shown, the truth table is:

A
$$\begin{matrix}A& B &Y \\ 0 & 0 &0 \\0 &1 &1 \\ 1 & 0 & 1 \\ 1 & 1 & 1\end{matrix}$$
B
$$\begin{matrix}A& B &Y \\ 0 & 0 &1 \\0 &1 &0 \\ 1 & 0 & 0 \\ 1 & 1 & 0\end{matrix}$$
C
$$\begin{matrix}A& B &Y \\ 0 & 0 &1 \\0 &1 &1 \\ 1 & 0 & 1 \\ 1 & 1 & 0\end{matrix}$$
D
$$\begin{matrix}A& B &Y \\ 0 & 0 &0 \\0 &1 &0 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{matrix}$$
Solution
Verified by Toppr

Correct option is D. $$\begin{matrix}A& B &Y \\ 0 & 0 &0 \\0 &1 &0 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{matrix}$$
The circuit consists of two NOT gates connected to each input of a NOR gate.

The correct truth table of the combination will be:
A B Y
0 0 0
0 1 0
1 0 0
1 1 1

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