For the reaction equilibrium 2NOBr-left - g right -leftrightharpoons2NO-left - g right - - Br-2left - g right - P-Br-2- dfrac-P-9- equilibrium and P is the initial total pressure- then the ratio dfrac-K-P-P- is equal to -dfrac-1-9-dfrac-4-441-dfrac-1-27-dfrac-1-3-

Question

Toppr Admin · Accepted Answer

The equilibrium reaction is 2NOBr-g-x21CB-2NO-g-Br2-g-

For the reaction equilibrium $2 N O B r_{(g)} ⇋ 2 N O_{(g)} + B r_{2 (g)}$ , if $P_{B r_{2}} = \frac{P}{9}$ at equilibrium and P is the initial total pressure, then the ratio $\frac{K_{P}}{P}$ is equal to :
$\frac{1}{9}$
$\frac{4}{441}$
$\frac{1}{27}$
$\frac{1}{3}$

The equilibrium reaction is $2 N O B r_{(g)} ⇋ 2 N O_{(g)} + B r_{2 (g)} .$

For the reaction equilibrium 2NOBr(g)⇋2NO(g)+Br2(g), if PBr2=P9 at equilibrium and P is the initial total pressure, then the ratio KPP is equal to :19444112713

The equilibrium reaction is 2NOBr(g)⇋2NO(g)+Br2(g).

For the reaction equilibrium $2 N O B r_{(g)} ⇋ 2 N O_{(g)} + B r_{2 (g)}$ , if $P_{B r_{2}} = \frac{P}{9}$ at equilibrium and P is the initial total pressure, then the ratio $\frac{K_{P}}{P}$ is equal to :
$\frac{1}{9}$
$\frac{4}{441}$
$\frac{1}{27}$
$\frac{1}{3}$

The equilibrium reaction is $2 N O B r_{(g)} ⇋ 2 N O_{(g)} + B r_{2 (g)} .$