For the reaction, $$A_{\left ( s \right )}+3B_{\left ( g \right )}\rightarrow 4C_{\left ( s \right )}+D_{\left ( l \right )}$$.
$$\Delta H$$ and $$\Delta U$$ are related as:
C
$$\Delta H=\Delta U+3RT$$
D
$$\Delta H=\Delta U-3RT$$
Correct option is D. $$\Delta H=\Delta U-3RT$$
(D) $$A_{\left ( s \right )}+3B_{\left ( g \right )}\rightarrow 4C_{\left ( s \right )}+D_{\left ( l \right )}$$
$$\Delta n_{g}=0-3=-3;$$
$$\Delta H=\Delta E+\Delta n_{g}RT$$ {$$\because \Delta E=\Delta U$$}
therefore, $$\Delta H=\Delta U-3RT$$