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Question

For the reaction $C_{2} H_{4} (g) + 3 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l)$ , the difference between enthalpy change and internal energy change is:

$- R T$
$+ R T$
$- 2 R T$
$+ 2 R T$

A

- R T

B

+ R T

C

- 2 R T

D

+ 2 R T

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Solution

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$C_{2} H_{4} (g) + 3 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l)$

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Similar Questions

Q1

For the reaction $C_{2} H_{4} (g) + 3 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l)$ , the difference between enthalpy change and internal energy change is:

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Q2

The enthalpy change for the reaction,

C_{2} H_{4} (g) + 3 O_{2} (g) ⟶ 2 C O_{2} (g) + 2 H_{2} O (g)

is called:

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Q3

The value of enthalpy change (

Δ H

) for the reaction

C_{2} H_{5} O H_{(l)} + 3 O_{2 (g)} \to 2 C O_{2 (g)} + 3 H_{2} O_{(l)}

at

27^{0}

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- 1366.5 k J m o l^{- 1}

. The value of internal energy change for the above reaction at this temperature be:

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Q4

Calculate the standard internal energy change for the reaction at 25⁰C:-

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CO₂ = - 393.5 kJ/mole H₂O = - 286 kJ/mole R = 8.314 J/K/mole.

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Q5

The enthalpy change for the reaction,

C_{2} H_{4} (g) + 3 O_{2} (g) ⟶ 2 C O_{2} (g) + 2 H_{2} O (g)

is called:

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