For the reaction-SO-2-g-frac-1-2-o-2-g-rightleftharpoons SO-3-g- K-p-K-C-RT-x- then x becomes-1-frac-1-2-frac-1-2-1

Question

Toppr Admin · Accepted Answer

The correct option is B -x2212-12Kp-Kc-RT-x-xA0-x-x394-ng-xA0- -xA0- -xA0-1-x2212-1-12-xA0- -xA0- -xA0- -x2212-12Hence- option B is correct-

For the reaction,

$S O_{2} (g) + \frac{1}{2} o_{2} (g) ⇌ S O_{3} (g)$

if $K_{p} = K_{C} (R T)^{x}$ , then x becomes:

$- 1$
$- \frac{1}{2}$
$\frac{1}{2}$
$1$