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Updated on : 2022-09-05

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Correct option is C)

$Case−1$

$S_{1}$ $immersed inair$

$(1)sin1=445 sinγ→sin_{2}i=(445 )_{2}(1−cos_{2}γ)$

$(445 )cosγ⩾(57 )1−4516 sin_{2}i=cos_{2}x−(1)Squaring$

$141_{2}45 cos_{2}γ⩾2549 (4)_{2}45 (1−4516 sin_{2}i)⩾2549 (4)_{2}45 −44sin_{2}i ⩾2549 1645 −2549 ⩾sin_{2}i $

$Case−(2)S_{2}immersed in water.$

$34 sini=445 sinγ916 sin_{2}i=1645 sin_{2}γ⇒1−9(45)(16)_{2} sin_{2}1=cos_{2}γ1645 cos_{2}γ⩾2549 1645 [1−9(45)(16)_{2} sin_{2}1]⩾,2549 ⇒1645 −2549 ⩾sin_{2}iSo optionc is correct $

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