For what value of E the potential of A is equal to the potential of B-

Question

Toppr Admin · Accepted Answer

Applying the KVL-15V-x2212-5i-x2212-2i-E-x2212-1i-0We get - i-15-E8A-1-now-xA0-VA-VBtherefore- VAB-0or E-x2212-ir-0putting-xA0- value of i from -1-E-5V

For what value of E the potential of A is equal to the potential of B?

Applying the KVL:
$15 V - 5 i - 2 i + E - 1 i = 0$
We get , $i = \frac{15 + E}{8}$ A..............(1)
now,
$V_{A} = V_{B}$
therefore, $V_{A B} = 0$
or $E - i r = 0$
putting value of i from (1),
$E = 5 V$

For what value of E the potential of A is equal to the potential of B?

Applying the KVL:15V−5i−2i+E−1i=0We get , i=15+E8A..............(1)now, VA=VBtherefore, VAB=0or E−ir=0putting value of i from (1),E=5V

Applying the KVL:
$15 V - 5 i - 2 i + E - 1 i = 0$
We get , $i = \frac{15 + E}{8}$ A..............(1)
now,
$V_{A} = V_{B}$
therefore, $V_{A B} = 0$
or $E - i r = 0$
putting value of i from (1),
$E = 5 V$