Four charges 10−8;−2×10−8;+3×10−8 and 2×10−8 coulombs are placed at the four corners of a square of side 1m. The potential at the centre of the square is
A
zero
B
360volt
C
180volt
D
3602volt
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Solution
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Correct option is D)
We know V due to a charge Q =rkQ
Potential at centre =(21)k(10−8)+(21)k(−2×10−8)+(21)k(2×10−8) +(21)k(3×10−8)
=k2(10−8+3×10−8) =4×10−8×9×109×2 =3602volts
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