Four die are thrown simultaneously- The probability that 4 and 3 appear on two of the die given that 5 and 6 have appeared on other two die is-12-1511-361-6None of these

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Toppr Admin · Accepted Answer

5 and 6 appeared on other two and its definite with probability-14 and 3 appears on remaining two like 4-3 or 3-4-2-1-6-1-6-1-18-xA0-

Four die are thrown simultaneously. The probability that $4$ and $3$ appear on two of the die given that $5$ and $6$ have appeared on other two die is?
$12 / 151$
$1 / 36$
$1 / 6$
None of these

5 and 6 appeared on other two and its definite with probability=1
4 and 3 appears on remaining two like 4,3 or 3,4=21/61/6=1/18

Four die are thrown simultaneously. The probability that 4 and 3 appear on two of the die given that 5 and 6 have appeared on other two die is?12/1511/361/6None of these

5 and 6 appeared on other two and its definite with probability=14 and 3 appears on remaining two like 4,3 or 3,4=2*1/6*1/6=1/18

Four die are thrown simultaneously. The probability that $4$ and $3$ appear on two of the die given that $5$ and $6$ have appeared on other two die is?
$12 / 151$
$1 / 36$
$1 / 6$
None of these

5 and 6 appeared on other two and its definite with probability=1
4 and 3 appears on remaining two like 4,3 or 3,4=21/61/6=1/18